document.write( "Question 123070: solve for x: 3x^2+4x-9=0 \n" ); document.write( "
Algebra.Com's Answer #90334 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Let's use the quadratic formula to solve for x:\r
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\n" ); document.write( "\n" ); document.write( "Starting with the general quadratic\r
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\n" ); document.write( "\n" ); document.write( "\"ax%5E2%2Bbx%2Bc=0\"\r
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\n" ); document.write( "\n" ); document.write( "the general solution using the quadratic equation is:\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29\"\r
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\n" ); document.write( "\n" ); document.write( "So lets solve \"3%2Ax%5E2%2B4%2Ax-9=0\" ( notice \"a=3\", \"b=4\", and \"c=-9\")\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-4+%2B-+sqrt%28+%284%29%5E2-4%2A3%2A-9+%29%29%2F%282%2A3%29\" Plug in a=3, b=4, and c=-9\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-4+%2B-+sqrt%28+16-4%2A3%2A-9+%29%29%2F%282%2A3%29\" Square 4 to get 16 \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-4+%2B-+sqrt%28+16%2B108+%29%29%2F%282%2A3%29\" Multiply \"-4%2A-9%2A3\" to get \"108\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-4+%2B-+sqrt%28+124+%29%29%2F%282%2A3%29\" Combine like terms in the radicand (everything under the square root)\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-4+%2B-+2%2Asqrt%2831%29%29%2F%282%2A3%29\" Simplify the square root (note: If you need help with simplifying the square root, check out this solver)\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-4+%2B-+2%2Asqrt%2831%29%29%2F6\" Multiply 2 and 3 to get 6\r
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\n" ); document.write( "\n" ); document.write( "So now the expression breaks down into two parts\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-4+%2B+2%2Asqrt%2831%29%29%2F6\" or \"x+=+%28-4+-+2%2Asqrt%2831%29%29%2F6\"\r
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\n" ); document.write( "\n" ); document.write( "Now break up the fraction\r
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\n" ); document.write( "\n" ); document.write( "\"x=-4%2F6%2B2%2Asqrt%2831%29%2F6\" or \"x=-4%2F6-2%2Asqrt%2831%29%2F6\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=-2+%2F+3%2Bsqrt%2831%29%2F3\" or \"x=-2+%2F+3-sqrt%2831%29%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "So these expressions approximate to\r
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\n" ); document.write( "\n" ); document.write( "\"x=1.18925478761001\" or \"x=-2.52258812094334\"\r
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\n" ); document.write( "\n" ); document.write( "So our solutions are:\r
\n" ); document.write( "\n" ); document.write( "\"x=1.18925478761001\" or \"x=-2.52258812094334\"\r
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\n" ); document.write( "\n" ); document.write( "Notice when we graph \"3%2Ax%5E2%2B4%2Ax-9\", we get:\r
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\n" ); document.write( "\n" ); document.write( "when we use the root finder feature on a calculator, we find that \"x=1.18925478761001\" and \"x=-2.52258812094334\".So this verifies our answer
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