document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=123078>Question 123078</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A mechanic is working on a car with a 20-qt radiator containing a 60% antifreeze solution.  HOw much of the solution should he drain and replace with pure water to get a solution that is 50% antifreeze. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #90320 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=90320\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .6(20-X)=.5*20<BR>\n" );
document.write( "12-.6X=10<BR>\n" );
document.write( "-.6X=10-12<BR>\n" );
document.write( "-.6X=-2<BR>\n" );
document.write( "X=-2/-.6<BR>\n" );
document.write( "X=3.33 QT NEEDS TO BE DRAINED & REPLACED WITH PURE WATER.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( ".6(20-3.33)=.5*20<BR>\n" );
document.write( ".6*16.67=10<BR>\n" );
document.write( "10=10<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );