document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=123075>Question 123075</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Julia's soybean field is 3 m longer than it is wide.  To increase her production, she plans to increase both the length and width by 2 m.  If the new field is 46m2 larger than the old field then what are the dimensions of the the old field? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #90318 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=90318\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> X & X+3 ARE THE MEASUREMENTS OF THE ORIGINAL FIELD.<BR>\n" );
document.write( "X(X+3)=X^2+3X FOR THE ORIGINAL FIELDS AREA.<BR>\n" );
document.write( "(X+2)(X+5)=X^2+7X+10 IS THE EXPANDED AREA.<BR>\n" );
document.write( "GIVEN THAT THE DIFFERENCE IS 46M^2 THEN WE HAVE:<BR>\n" );
document.write( "X^2+3X+46=X^2+7X+10<BR>\n" );
document.write( "X^2-X^2+3X-7X=-46+10<BR>\n" );
document.write( "-4X=-36<BR>\n" );
document.write( "X=-36/-4<BR>\n" );
document.write( "X=9M FOR ONE OF THE ORIGINAL WIDTH.<BR>\n" );
document.write( "9+3=12M FOR THE ORIGINAL LENGTH.<BR>\n" );
document.write( "9*12=108 M^2 FOR THE ORIGINAL FIELD.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "9+2=11 & 12+2=14 <BR>\n" );
document.write( "11*14=154 M^2<BR>\n" );
document.write( "154-46=108<BR>\n" );
document.write( "108=108 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );