document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=122957>Question 122957</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/003052217x/algebrahomeworkh>algebra1</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> My daughter and I have been working on this one problem for an hour, we know the answer, but do not know how to get the answer, here it is\r<BR>\n" );
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document.write( "y+3x=1<BR>\n" );
document.write( "2y+5x=5  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #90293 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=90293\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> multiplying first equation by -2 __ -2y-6x=-2\r<BR>\n" );
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document.write( "adding second equation __ (-2y-6x)+(2y+5x)=(-2)+(5) __ -x=3 __ x=-3\r<BR>\n" );
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document.write( "substituting __ y+3(-3)=1 __ y=10 </SPAN>\n" );
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