document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=122865>Question 122865</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Before the final exam,, a student has test scores of 72, 80, 65, 78, and 60.  If the final exam counts as one-third of the final grade, what score must the \r<BR>\n" );
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document.write( "student receive in order to have a final average of 76?\r<BR>\n" );
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document.write( "I tried the equation:  [355(2/3) + 1/3x]   = 76<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #90221 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=90221\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (72+80+65+78+60)/5<BR>\n" );
document.write( "355/5=71 AVERAGE FOR THE FIRST 5 TEST RESULTS.<BR>\n" );
document.write( "71*2/3+1/3X=76 CALCULATING 2/3 OF THE FIRST 5 TESTS + 1/3 OF THE FINAL TEST SCORE.<BR>\n" );
document.write( "142/3+X/3=76<BR>\n" );
document.write( "47.33+X/3=76<BR>\n" );
document.write( "X/3=76-47.33<BR>\n" );
document.write( "X/3=28.67<BR>\n" );
document.write( "X=3*28.67<BR>\n" );
document.write( "X=86 IS THE REQUIRED TEST SCORE ON THE FINAL TEST TO AVERAGE 76. </SPAN>\n" );
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