document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=122879>Question 122879</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sides of ne triangle have lengths 8, 15, and 17. The perimeter of a similar triangle is 120. Find the lengths of the sides of the second triangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #90217 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=90217\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 8+15+17=40<BR>\n" );
document.write( "120/40=3 this is the multiplier for all sides. THUS:<BR>\n" );
document.write( "8*3=24<BR>\n" );
document.write( "15*3=45<BR>\n" );
document.write( "17*3=51<BR>\n" );
document.write( "proof:<BR>\n" );
document.write( "24+45+51=120<BR>\n" );
document.write( "120=120<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );