document.write( "Question 122834: please can you show me a method of how to work out this equation x^2+9x+14=0 \n" ); document.write( "
Algebra.Com's Answer #90171 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Solve for x:
\n" ); document.write( "\"x%5E2%2B9x%2B14+=+0\" You can always solve a quadratic equation using the quadratic formula:
\n" ); document.write( "\"x+=+%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F2a\" and, of course, the a, b, and c come from the standard form of the equation:
\n" ); document.write( "\"ax%5E2%2Bbx%2Bc+=+0\"
\n" ); document.write( "So, in this case, a = 1, b = 9, and c = 14
\n" ); document.write( "Making the appropriate substitutions into the quadratic formula, we get:
\n" ); document.write( "\"x+=+%28-9%2B-sqrt%289%5E2-4%281%29%2814%29%29%29%2F2%281%29\"
\n" ); document.write( "\"x+=+%28-9%2B-sqrt%2881-56%29%29%2F2\"
\n" ); document.write( "\"x+=+%28-9%2B-sqrt%2825%29%29%2F2\"
\n" ); document.write( "\"x+=+%28-9%2B5%29%2F2\" or \"x+=+%28-9-5%29%2F2\"
\n" ); document.write( "\"x+=+-2\" or \"x+=+-7\"\r
\n" ); document.write( "\n" ); document.write( "If the given trinomial can be factored, this offers another way to solve the problem:
\n" ); document.write( "\"x%5E2%2B9x%2B14+=+0\" Factor the trinomial.
\n" ); document.write( "\"%28x%2B2%29%28x%2B7%29+=+0\" Apply the zero product principle.
\n" ); document.write( "\"x%2B2+=+0\" or \"x%2B7+=+0\", then...
\n" ); document.write( "If \"x%2B2+=+0\" then \"x+=+-2\"
\n" ); document.write( "If \"x%2B7+=+0\" then \"x+=+-7\"
\n" ); document.write( "So in both cases, you get the same solutions:
\n" ); document.write( "\"x+=+-2\"
\n" ); document.write( "\"x+=+-7\"
\n" ); document.write( "A third way would be to graph the equation (\"y+=+x%5E2%2B9x%2B14\") and identify the x-intercepts (also called \"the zeros\").
\n" ); document.write( "\"graph%28600%2C400%2C-8%2C5%2C-8%2C5%2Cx%5E2%2B9x%2B14%29\"
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