document.write( "Question 122805: If the smallest of the three consecutive integer is added to twice the largest, the result is seven less than four times the middle. Find the nos \n" ); document.write( "
Algebra.Com's Answer #90156 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! : If the smallest of the three consecutive integer is added to twice the largest, the result is seven less than four times the middle. Find the nos \n" ); document.write( ": \n" ); document.write( "The three consecutive integers: x, (x+1), (x+2) \n" ); document.write( ": \n" ); document.write( "x + 2(x+2) = 4(x+1) - 7 \n" ); document.write( ": \n" ); document.write( "x + 2x + 4 = 4x + 4 - 7 \n" ); document.write( ": \n" ); document.write( "3x + 4 = 4x - 3 \n" ); document.write( ": \n" ); document.write( "3x - 4x = -3 - 4 \n" ); document.write( ": \n" ); document.write( "-x = -7 \n" ); document.write( ": \n" ); document.write( "x = +7, 8, 9 are the three integers \n" ); document.write( ": \n" ); document.write( "Check solution in the statement: \n" ); document.write( "\"If the smallest of the three consecutive integers, is added to twice the largest, the result is seven less than four times the middle. \" \n" ); document.write( "7 + 2(9) = 4(8) - 7 \n" ); document.write( "7 + 18 = 32 - 7; confirms our solution \n" ); document.write( ": \n" ); document.write( "Not that hard, right? \n" ); document.write( " |