document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=122779>Question 122779</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of the lengths of one side of a right triangle and the hypotenuse is 20cm. The other leg is 5cm shorter than the hypotenuse.  Find the length of each side.\r<BR>\n" );
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document.write( "x^2+(x-5)^2=20^2<BR>\n" );
document.write( "x^2+x^2-25x+25=400<BR>\n" );
document.write( "2x^2-25x-375=0<BR>\n" );
document.write( "x^2-5x-178.50=0\r<BR>\n" );
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document.write( "I just want to double check my steps to make sure I did this right.  Thanks is advance. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #90146 by </B><A HREF=/tutors/aboutme.mpl?userid=GSems22><B>GSems22(3)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=GSems22><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=90146\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Your answer appears correct in my eyes.  That would be how I would solve it. Good Job! </SPAN>\n" );
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