document.write( "Question 122761: Solve.\r
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document.write( "The longer leg of a right triangle is 3 cm less than twice the shorter leg. The hypotenuse is 18 cm long. Find the length of the shorter leg. \n" );
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Algebra.Com's Answer #90124 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! X^2+(2X-3)^2=18^2 \n" ); document.write( "X^2+4X^2-12X+9=324 \n" ); document.write( "5X^2-12X+9-324=0 \n" ); document.write( "5X^2-12X-315=0 \n" ); document.write( " \n" ); document.write( "X=(12+-SQRT[-12^2-4*5*-315])/2*5 \n" ); document.write( "X=(12+-SQRT[144+6300])/10 \n" ); document.write( "X=(12+-SQRT6444)/10 \n" ); document.write( "X=(12+-80.27)/10 \n" ); document.write( "X=(12+80.27)/10 \n" ); document.write( "X=92.27/10 \n" ); document.write( "X=9.227 ANSWER FOR THE SHORTER LEG. \n" ); document.write( "2*9.227-3=18.454-3=15.454 FOR THE LONGER LEG. \n" ); document.write( "PROOF \n" ); document.write( "9.227^2+15.454^2=324 \n" ); document.write( "85.138+238.826=324 \n" ); document.write( "324~324 \n" ); document.write( " \n" ); document.write( " |