document.write( "Question 122621: find an equation with coefficients whose roots are 2 plus and minus the square root of 3 divided by 3 \n" ); document.write( "
Algebra.Com's Answer #90123 by ankor@dixie-net.com(22740)\"\" \"About 
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find an equation with coefficients whose roots are 2 plus and minus the square root of 3 divided by 3
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\n" ); document.write( "x = \"%282%2B-sqrt%283%29%29%2F3\"
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\n" ); document.write( "Multiply both sides by 3:
\n" ); document.write( "3x = \"2%2B-sqrt%283%29\"
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\n" ); document.write( "Subtract 2 from both sides
\n" ); document.write( "3x - 2 = +/-\"sqrt%283%29\"
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\n" ); document.write( "Square both sides:
\n" ); document.write( "(3x-2)^2 = 3
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\n" ); document.write( "FOIL
\n" ); document.write( "9x^2 - 12x + 4 = 3
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\n" ); document.write( "Subtract 3 from both sides:
\n" ); document.write( "9x^2 - 12x + 4 - 3 = 0
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\n" ); document.write( "9x^2 - 12x + 1 = 0 is our equation
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