document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=2227>Question 2227</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a rhombus with a 24 cm diagonal has an area of 120 cm sqaured . find the length of a side of the rhombus </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #901 by </B><A HREF=/tutors/aboutme.mpl?userid=khwang><B>khwang(438)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=khwang><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=901\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  Since the area rhombus = product of the two diagonals<BR>\n" );
document.write( " Now, 120 = 24 * another diagonal, so another diagonal = 5.<BR>\n" );
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document.write( " Let x be the length of a side of the rhombus,<BR>\n" );
document.write( " we have x^2 = (24/2)^2 + (5/2)^2 = 144 + 25/4 = 601 /4<BR>\n" );
document.write( " So, x = sqrt(601)/2<BR>\n" );
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