document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=122691>Question 122691</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this word problem!!!!\r<BR>\n" );
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document.write( "A factory is to be built on a lot that measures 80m by 60m. A lawn of uniform width, equal to the area of the factory, must surround it. How wide is the strip of lawn, and what are the dimensions of the factory?\r<BR>\n" );
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document.write( "The answers should be 10m, 60m by 40m.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #90081 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=90081\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A factory is to be built on a lot that measures 80m by 60m. A lawn of uniform width, equal to the area of the factory, must surround it. How wide is the strip of lawn, and what are the dimensions of the factory? <BR>\n" );
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document.write( "Find the area of the lot<BR>\n" );
document.write( "80 * 60 = 4800<BR>\n" );
document.write( "Then<BR>\n" );
document.write( "4800/2 = 2400 is the area of the factory (also the area of the lawn).<BR>\n" );
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document.write( "Let x = the width of the lawn:<BR>\n" );
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document.write( "Make a rough drawing of this, a rectangle (factory) inside a a larger rectangle.<BR>\n" );
document.write( "Label the width of strip around the factor as x. Label the lot 80 by 60<BR>\n" );
document.write( "It will be apparent that factory will be (80-2x) by (60-2x)<BR>\n" );
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document.write( "Therefore we have an area equation of:<BR>\n" );
document.write( "(80-2x)*(60-2x) = 2400<BR>\n" );
document.write( "FOIL<BR>\n" );
document.write( "4800 - 160x - 120x + 4x^2 = 2400<BR>\n" );
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document.write( "4x^2 - 280x + 4800 - 2400 = 0; arrange as a quadratic equation<BR>\n" );
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document.write( "4x^2 + 280x + 2400<BR>\n" );
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document.write( "Divide equation by 4 to simplify<BR>\n" );
document.write( "x^2 + 70x + 600 = 0<BR>\n" );
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document.write( "Factors to:<BR>\n" );
document.write( "(x-10)(x-60) = 0<BR>\n" );
document.write( "x = +60, not a reasonable answer<BR>\n" );
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document.write( "x = 10 m is the width of the lawn around the factory<BR>\n" );
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document.write( "The dimension of the factory then<BR>\n" );
document.write( "80 - 20 = 60m<BR>\n" );
document.write( "60 - 20 = 40m<BR>\n" );
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document.write( "Check solution finding the areas<BR>\n" );
document.write( "Lot area80*60 = 4800<BR>\n" );
document.write( "Factory 60*40 = 2400<BR>\n" );
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document.write( "minus is lawn = 2400<BR>\n" );
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