document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=122718>Question 122718</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The hypotenuse of a right triangle is 26 cm. The sum of the other two sides is 34 cm. Find the lengths of the other two sides of the triangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #90079 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=90079\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x^2+(34-x)^2=26^2<BR>\n" );
document.write( "x^2+1156-68x+x^2=676<BR>\n" );
document.write( "2x^2-68x+1156-676=0<BR>\n" );
document.write( "2x^2-68x+480=0<BR>\n" );
document.write( "2(x^2-34x+240)=0<BR>\n" );
document.write( "2(x-24)(x-10)=0<BR>\n" );
document.write( "x-24=o x=24 answer.<BR>\n" );
document.write( "x-10=0<BR>\n" );
document.write( "x=10 answer.<BR>\n" );
document.write( "therefore the sides are 10 & 24 cm.<BR>\n" );
document.write( "proof<BR>\n" );
document.write( "10*2+24^2=676<BR>\n" );
document.write( "100+576=676<BR>\n" );
document.write( "676=676<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );