document.write( "Question 122670: A rectangular field is 200m by 300m. A roadway of width xm is to be built just inside the field. What is the widest the roadway can be and still leave 50,000m^2 in the region?\r
\n" ); document.write( "\n" ); document.write( "60,000 - 400x - 600x +x = 50,000\r
\n" ); document.write( "\n" ); document.write( "Am I on the right track for solving the problem with this formula? I feel like I'm missing something.
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Algebra.Com's Answer #90062 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
First let's draw a picture. We can see that the length of the inner rectangle is \"300-2x\" and the width of the inner rectangle is \"200-2x\" since we are taking away \"2x\" from both the length and the width.\r
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\n" ); document.write( "\n" ); document.write( "note: the inner rectangle represents the remaining area\r
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\n" ); document.write( "\n" ); document.write( "From the drawing, the area of remaining area is (ie the blue rectangle):\r
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\n" ); document.write( "\n" ); document.write( "\"A=%28300-2x%29%28200-2x%29\" \r
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\n" ); document.write( "\n" ); document.write( "\"A=%28300-2x%29%28200-2x%29\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"50000=%28300-2x%29%28200-2x%29\" Plug in A=50,000\r
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\n" ); document.write( "\n" ); document.write( "\"50000=4x%5E2-1000x%2B60000\" Foil\r
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\n" ); document.write( "\n" ); document.write( "\"0=4x%5E2-1000x%2B60000-50000\" Subtract 50,000 from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"0=4x%5E2-1000x%2B10000\" Combine like terms\r
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\n" ); document.write( "\n" ); document.write( "Let's use the quadratic formula to solve for x:\r
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\n" ); document.write( "\n" ); document.write( "Starting with the general quadratic\r
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\n" ); document.write( "\n" ); document.write( "\"ax%5E2%2Bbx%2Bc=0\"\r
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\n" ); document.write( "\n" ); document.write( "the general solution using the quadratic equation is:\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29\"\r
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\n" ); document.write( "\n" ); document.write( "So lets solve \"4%2Ax%5E2-1000%2Ax%2B10000=0\" ( notice \"a=4\", \"b=-1000\", and \"c=10000\")\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28--1000+%2B-+sqrt%28+%28-1000%29%5E2-4%2A4%2A10000+%29%29%2F%282%2A4%29\" Plug in a=4, b=-1000, and c=10000\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%281000+%2B-+sqrt%28+%28-1000%29%5E2-4%2A4%2A10000+%29%29%2F%282%2A4%29\" Negate -1000 to get 1000\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%281000+%2B-+sqrt%28+1000000-4%2A4%2A10000+%29%29%2F%282%2A4%29\" Square -1000 to get 1000000 \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%281000+%2B-+sqrt%28+1000000%2B-160000+%29%29%2F%282%2A4%29\" Multiply \"-4%2A10000%2A4\" to get \"-160000\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%281000+%2B-+sqrt%28+840000+%29%29%2F%282%2A4%29\" Combine like terms in the radicand (everything under the square root)\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%281000+%2B-+200%2Asqrt%2821%29%29%2F%282%2A4%29\" Simplify the square root (note: If you need help with simplifying the square root, check out this solver)\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%281000+%2B-+200%2Asqrt%2821%29%29%2F8\" Multiply 2 and 4 to get 8\r
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\n" ); document.write( "\n" ); document.write( "So now the expression breaks down into two parts\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%281000+%2B+200%2Asqrt%2821%29%29%2F8\" or \"x+=+%281000+-+200%2Asqrt%2821%29%29%2F8\"\r
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\n" ); document.write( "\n" ); document.write( "Now break up the fraction\r
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\n" ); document.write( "\n" ); document.write( "\"x=%2B1000%2F8%2B200%2Asqrt%2821%29%2F8\" or \"x=%2B1000%2F8-200%2Asqrt%2821%29%2F8\"\r
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\n" ); document.write( "\n" ); document.write( "Simplify\r
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\n" ); document.write( "\n" ); document.write( "\"x=125%2B25%2Asqrt%2821%29\" or \"x=125-25%2Asqrt%2821%29\"\r
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\n" ); document.write( "\n" ); document.write( "So these expressions approximate to\r
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\n" ); document.write( "\n" ); document.write( "\"x=239.564392373896\" or \"x=10.435607626104\"\r
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\n" ); document.write( "\n" ); document.write( "So our possible solutions are:\r
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\n" ); document.write( "\n" ); document.write( "\"x=239.564392373896\" or \"x=10.435607626104\"\r
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\n" ); document.write( "\n" ); document.write( "However, if you plug in \"x=239.564392373896\" into \"A=%28300-2x%29%28200-2x%29\" , it will give you a negative area, so our only solution is \r
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\n" ); document.write( "\n" ); document.write( "\"x=10.435607626104\"\r
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\n" ); document.write( "\n" ); document.write( "So the roadway can be about 10.44 m wide which will leave 50,000 m^2 of field\r
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