document.write( "Question 122660: The length of a rectangle is 3 in. more than twice its width. If the perimeter of the rectangle is 36 in., what's the width of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #90060 by jim_thompson5910(35256)\"\" \"About 
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Let L=length, w=width\r
\n" ); document.write( "\n" ); document.write( "Since the length is \"3 in. more than twice its width\", this means: \"L=2w%2B3\"\r
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\n" ); document.write( "\n" ); document.write( "\"P=2w%2B2L\" Start with the perimeter formula\r
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\n" ); document.write( "\n" ); document.write( "\"36=2w%2B2%282w%2B3%29\" Plug in the given perimeter \"P=36\" and \"L=2w%2B3\"\r
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\n" ); document.write( "\n" ); document.write( "\"36=2w%2B4w%2B6\" Distribute\r
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\n" ); document.write( "\n" ); document.write( "\"36=6w%2B6\" Combine like terms on the right side\r
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\n" ); document.write( "\n" ); document.write( "\"0=6w%2B6-36\"Subtract 36 from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"-6w=6-36\" Subtract 6w from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"-6w=-30\" Combine like terms on the right side\r
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\n" ); document.write( "\n" ); document.write( "\"w=%28-30%29%2F%28-6%29\" Divide both sides by -6 to isolate w\r
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\n" ); document.write( "\n" ); document.write( "\"w=5\" Divide\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
\n" ); document.write( "\n" ); document.write( "So our answer is \"w=5\" \r
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\n" ); document.write( "\n" ); document.write( "So the width is 5 inches
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