document.write( "Question 122663: If the value of b^2-4ac is negative, the equation ax^2+bx+c=0. Is there always a real number solution? \n" ); document.write( "
Algebra.Com's Answer #90058 by jim_thompson5910(35256)\"\" \"About 
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By definition: if \"b%5E2-4ac%3C0\" (ie if it's negative) then the quadratic will never have real solutions. It will have two complex solutions. \n" ); document.write( "
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