document.write( "Question 122603: In four years time a mother will be three times as old as her son. Four years go she was five times as old as her son. Find their present ages. \n" ); document.write( "
Algebra.Com's Answer #90039 by oscargut(2103)![]() ![]() You can put this solution on YOUR website! Let M= present age of the mother and S= present age of the son\r \n" ); document.write( "\n" ); document.write( "In four years time a mother will be three times as old as her son \n" ); document.write( "so (M+4)=3(S+4)\r \n" ); document.write( "\n" ); document.write( "Four years ago she was five times as old as her son.\r \n" ); document.write( "\n" ); document.write( "so (M-4)=5(S-4)\r \n" ); document.write( "\n" ); document.write( "if you simplify the equations:\r \n" ); document.write( "\n" ); document.write( "M+4=3S+12 \n" ); document.write( "M-4=5S-20\r \n" ); document.write( "\n" ); document.write( "M-3S=8 \n" ); document.write( "M-5S=-16\r \n" ); document.write( "\n" ); document.write( "so substracting 2S=24 so S=12 using first equation \n" ); document.write( "M-3S=8 then M-36=8 and M=44\r \n" ); document.write( "\n" ); document.write( "R: M=44 and S=18\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |