document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=122574>Question 122574</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given that one of the zeros is -3, find the other zeros for this polynomial function: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=f%28x%29=x%5E3%2Bx%5E2%2B2x%2B24 ALIGN=MIDDLE  ALT=\"f%28x%29=x%5E3%2Bx%5E2%2B2x%2B24\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #90012 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=90012\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if -3 is a zero, then x+3 is a factor __ (x^3+x^2+2x+24)/(x+3)=x^2-2x+8\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "x^2-2x+8=0 __ not factorable __ use quadratic formula to find zeroes<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );