document.write( "Question 122552: An investor received $1400 interest per annum from a sum of money, with part of it invested at 10% and the remainder at 7% simple interest. This investor found that if she interchanged the amounts she had invested she could increase her return by $90 per annum. Calculate the total amount invested. \n" ); document.write( "
Algebra.Com's Answer #90003 by edjones(8007)![]() ![]() You can put this solution on YOUR website! A) .1x+.07y=1400 \n" ); document.write( "B) .07x+.1y=1490 \n" ); document.write( ". \n" ); document.write( "A) \n" ); document.write( ".1x=1400-.07y \n" ); document.write( "x=14000-.7y multiply each side by 10. \n" ); document.write( ". \n" ); document.write( "B) \n" ); document.write( ".07(14000-.7y)+.1y=1490 \n" ); document.write( "980-.049y+.1y=1490 \n" ); document.write( ".051y=510 \n" ); document.write( "y=10000 \n" ); document.write( ". \n" ); document.write( "A) \n" ); document.write( ".1x+.07(10000)=1400 \n" ); document.write( ".1x+700=1400 \n" ); document.write( ".1x=700 \n" ); document.write( "x=7000 \n" ); document.write( ". \n" ); document.write( "Check: \n" ); document.write( "B) \n" ); document.write( ".07(7000)+.1(10000)=1490 \n" ); document.write( "490+1000=1490 true \n" ); document.write( ". \n" ); document.write( "Ed \n" ); document.write( " |