document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=122573>Question 122573</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello, i'm trying to solve this: x^2-2x-4=0. I mean x to the 2nd power minus 2x minus 4 =0   okay, i tried to FOIL this problem and it doesn't work. please help. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #89985 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=89985\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> FOIL DOESN'T WORK FOR THESE EQUATIONS.<BR>\n" );
document.write( "YOU NEED THE QUADRATIC EQUATION TO SOLVE THIS ONE.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+ ALIGN=MIDDLE  ALT=\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "X^2-2X-4=0<BR>\n" );
document.write( "X=(2+-SQRT[-2^2-4*1*-4])/2*1<BR>\n" );
document.write( "X=(2+-SQRT[4+16])/2<BR>\n" );
document.write( "X=(2+-SQRT20)/2<BR>\n" );
document.write( "X=(2+4.472)/2<BR>\n" );
document.write( "X=(2+4.472)/2<BR>\n" );
document.write( "X=6.472/2<BR>\n" );
document.write( "X=3.236 ANSWER.<BR>\n" );
document.write( "X=(2-4.472)/2<BR>\n" );
document.write( "X=-2.472/2<BR>\n" );
document.write( "X=-1.236 ANSWER.\r<BR>\n" );
document.write( "<BR>\n" );
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document.write( " </SPAN>\n" );
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