document.write( "Question 122491: Solve the equation. 2y^2-3y-6=0 \n" ); document.write( "
Algebra.Com's Answer #89967 by Fombitz(32388)\"\" \"About 
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\"2y%5E2-3y-6=0\"
\n" ); document.write( "\"y+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\" Use the quadratic equation.
\n" ); document.write( "\"y+=+%28-%28-3%29+%2B-+sqrt%28+%28-3%29%5E2-4%2A2%2A%28-6%29+%29%29%2F%282%2A2%29+\"
\n" ); document.write( "\"y+=+%283+%2B-+sqrt%28+9%2B48+%29%29%2F%284%29+\"
\n" ); document.write( "\"y+=+%283+%2B-+sqrt%28+57+%29%29%2F%284%29+\" Two real solutions.
\n" ); document.write( "Exactly the roots are,
\n" ); document.write( "\"y%5B1%5D+=+%283+%2B+sqrt%28+57+%29%29%2F%284%29+\"
\n" ); document.write( "\"y%5B2%5D+=+%283+-+sqrt%28+57+%29%29%2F%284%29+\"
\n" ); document.write( "or approximately,
\n" ); document.write( "\"y%5B1%5D+=+2.637\"
\n" ); document.write( "\"y%5B2%5D+=+-1.137\"
\n" ); document.write( "\"+graph%28+300%2C+300%2C+-5%2C+5%2C+-5%2C+5%2C+2x%5E2-3x-6%29+\"
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