document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=122435>Question 122435</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help. <BR>\n" );
document.write( "A rancher has 100 meters of fencing to enclose two adjacent rectangular corrals.<BR>\n" );
document.write( "                                    4x + 3y = 100\r<BR>\n" );
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document.write( "Write the area A of the enclosed region as a function of x\r<BR>\n" );
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document.write( "So far this is what I&#8217;ve got-I figured out the function of x and plugged it into the Area formula, but that&#8217;s where I get stuck.<BR>\n" );
document.write( "P = 100<BR>\n" );
document.write( "4x + 3y = 100<BR>\n" );
document.write( "4x + 3y &#8211; 3y = &#8211; 3y + 100 <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4x+=+%28%26%238211%3B+3y+%2B+100%29%2F4 ALIGN=MIDDLE  ALT=\"4x+=+%28%26%238211%3B+3y+%2B+100%29%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( " <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+-3%2F4y+%2B+25 ALIGN=MIDDLE  ALT=\"x+=+-3%2F4y+%2B+25\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=f%28x%29+=-3%2F4y+%2B+25 ALIGN=MIDDLE  ALT=\"f%28x%29+=-3%2F4y+%2B+25\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "A = 2x(y)<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A+=%5B+2%28-3%2F4y+%2B+25%29%5Dy ALIGN=MIDDLE  ALT=\"A+=%5B+2%28-3%2F4y+%2B+25%29%5Dy\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A+=+%28-3%2F2y+%2B+50%29y ALIGN=MIDDLE  ALT=\"A+=+%28-3%2F2y+%2B+50%29y\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A+=+-3%2F2y%5E2+%2B+50y ALIGN=MIDDLE  ALT=\"A+=+-3%2F2y%5E2+%2B+50y\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( " I know x = 10 and y = 20 works for the perimeter, but don&#8217;t know how to write it to show that. When I graph <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A+=+-3%2F2y%5E2+%2B+50y ALIGN=MIDDLE  ALT=\"A+=+-3%2F2y%5E2+%2B+50y\"   DISABLED_style= \"max-width:90%; height:auto;\" > (making A correspond to y and the y correspond to the x), I don&#8217;t get the same area as in the table.<BR>\n" );
document.write( "I need to add more values to the table.<BR>\n" );
document.write( "X	Y	Area<BR>\n" );
document.write( "2	92/3	368/3 &#8776;123<BR>\n" );
document.write( "4	28	224<BR>\n" );
document.write( "Thank you for any help you can give!!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #89948 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=89948\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 4x + 3y = 100 __ subtracting 4x __ 3y=100-4x __ dividing by 3 __ y=(100-4x)/3\r<BR>\n" );
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document.write( "A = 2x(y) __ substituting for y __ A=2x(100-4x)/3 __ A=(200x-8x^2)/3\r<BR>\n" );
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document.write( "so f(x)=(200x-8x^2)/3 </SPAN>\n" );
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