document.write( "Question 122527: I'm having a hard time figuring out the answer to this problem, and even figuring out the correct set up for the equation. Thanks for any help provided!
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\n" ); document.write( "One number is eleven more than twice another. If their sum is decreased by ten, the result is thirteen. Find the numbers.
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\n" ); document.write( "this is what i know
\n" ); document.write( "one number is x
\n" ); document.write( "one number is elven more x+11
\n" ); document.write( "twice another 2x
\n" ); document.write( "sum decreased by ten is thirteen x-10=13
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Algebra.Com's Answer #89942 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "let numbers be \"x\" and \"y\", and let sat \"x%3Ey\"\r
\n" ); document.write( "\n" ); document.write( "if one number is \"eleven\" more than \"twice\" another, then you have:\r
\n" ); document.write( "\n" ); document.write( "\"x+=+2y+%2B+11\"......................(1)\r
\n" ); document.write( "\n" ); document.write( " if their \"sum\" is \"decreased\" by ten, the result is \"13\". means:\r
\n" ); document.write( "\n" ); document.write( "\"%28x%2By%29-10+=+13\"...or\r
\n" ); document.write( "\n" ); document.write( "\"x+%2B+y+=+23\"......................(2)\r
\n" ); document.write( "\n" ); document.write( "now solve the system to find the numbers.:\r
\n" ); document.write( "\n" ); document.write( "\"x+=+2y+%2B+11\"......................(1)...this one is solved for \"x\"; so plug \"x\" into (2)\r
\n" ); document.write( "\n" ); document.write( "\"2y+%2B+11+%2B+y+=+23\"......................(2)\r
\n" ); document.write( "\n" ); document.write( " \"2y+%2B+11+%2B+y+=+23\".............\r
\n" ); document.write( "\n" ); document.write( " \"3y++=+23+-11+\".............\r
\n" ); document.write( "\n" ); document.write( " \"3y++=+12\".............\r
\n" ); document.write( "\n" ); document.write( " \"y++=+4\".............\r
\n" ); document.write( "\n" ); document.write( "\"x+=+2y+%2B+11\"......................(1)...plug in \"y\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=+2%2A4+%2B+11\"..............\r
\n" ); document.write( "\n" ); document.write( "\"x+=+19\"..............\r
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