document.write( "Question 122531: 17) If log 3 = 1.4 and log 5 = 3.6, log 25/3=\r
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\n" ); document.write( "\n" ); document.write( "a) 8.6\r
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Algebra.Com's Answer #89941 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"log%285%29=3.6\" Start with the second equation\r
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\n" ); document.write( "\n" ); document.write( "\"2%2Alog%285%29=7.2\" Multiply both sides by 2\r
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\n" ); document.write( "\n" ); document.write( "\"log%285%5E2%29=7.2\" Rewrite the left side using the identity \"y%2Alog%28x%29=log%28x%5Ey%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"log%2825%29=7.2\" Square 5 to get 25\r
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\n" ); document.write( "\n" ); document.write( "So let's make our third equation be: \"log%2825%29=7.2\" \r
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\n" ); document.write( "\n" ); document.write( "\"log%2825%2F3%29\" Start with the given expression\r
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\n" ); document.write( "\n" ); document.write( "\"log%2825%29-log%283%29\" Expand the expression using \"log%28a%2Fb%29=log%28a%29-log%28b%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"7.2-1.4\" Replace \"log%2825%29\" with 7.2 ( remember \"log%2825%29=7.2\"). Replace \"log%283%29\" with 1.4 ( remember this was given: \"log%283%29=1.4\"). \r
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\n" ); document.write( "\n" ); document.write( "\"5.8\" Subtract\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
\n" ); document.write( "\n" ); document.write( "So \"log%2825%2F3%29=5.8\" \r
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\n" ); document.write( "\n" ); document.write( "This means that the answer is D)\r
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