document.write( "Question 122531: 17) If log 3 = 1.4 and log 5 = 3.6, log 25/3=\r
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document.write( "a) 8.6\r
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document.write( "b) -0.8\r
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document.write( "c) 3.4\r
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document.write( "d) 5.8\r
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document.write( "e) 6.2\r
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document.write( "
Algebra.Com's Answer #89941 by jim_thompson5910(35256) ![]() You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So let's make our third equation be: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-----------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answer:\r \n" ); document.write( "\n" ); document.write( "So \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This means that the answer is D)\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |