document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=122434>Question 122434</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle measures 4 cm less than 4 times the width. If the area is 31.0 cm^2, find the dimensions.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #89897 by </B><A HREF=/tutors/aboutme.mpl?userid=ddreamfox><B>ddreamfox(6)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ddreamfox><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=89897\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = width<BR>\n" );
document.write( "    4x-4 = length (4 cm less than 4 times the width)<BR>\n" );
document.write( "since Area  = length X width\r<BR>\n" );
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document.write( "Substitute values... to eqtn of Area\r<BR>\n" );
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document.write( "31 = x(4x-4)<BR>\n" );
document.write( "31 = 4x2 - 4x<BR>\n" );
document.write( "0 = 4x2 - 4x - 31<BR>\n" );
document.write( "Using quadratic formula,<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+ ALIGN=MIDDLE  ALT=\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "You'll get 2 values 1 positive and 1 negative...<BR>\n" );
document.write( "The correct answer is the positive answer which is 3.328cm (rounded off) </SPAN>\n" );
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