document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=122440>Question 122440</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 68cm. The length is 4cm more than the width. Fine the dimention of the rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #89891 by </B><A HREF=/tutors/aboutme.mpl?userid=gems><B>gems(12)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=gems><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=89891\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P = 68 cm<BR>\n" );
document.write( "L = 4 + W\r<BR>\n" );
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document.write( "Formula:<BR>\n" );
document.write( "P= 2L + 2W<BR>\n" );
document.write( "68 = 2(4+w) + 2W<BR>\n" );
document.write( "68 = 8 + 2W + 2W<BR>\n" );
document.write( "68 - 8 = 4W<BR>\n" );
document.write( "60 = 4W<BR>\n" );
document.write( "15 = W\r<BR>\n" );
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document.write( "If W = 15<BR>\n" );
document.write( "L = 4 + w<BR>\n" );
document.write( "L = 4 + 15<BR>\n" );
document.write( "L = 19\r<BR>\n" );
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document.write( "Therefore <BR>\n" );
document.write( "the dimension is 15 cm by 19 cm<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );