document.write( "Question 122365: please help me with this problem.\r
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\n" ); document.write( "\n" ); document.write( "this is a division problem, I wasn't certain how to show it in this format. \n" ); document.write( "
Algebra.Com's Answer #89854 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "I think you meant \"%28x%5E2%2B2x-36%29%2F%28x%2B4%29\".  You don't say, so I'm going to assume that you mean polynomial long division.\r\n" );
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\"x\"First term of divisor into first term of dividend
\"x%2B4\"\"x%5E2%2B2x-36\"
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\"x\"
\"x%2B4\"\"x%5E2%2B2x-36\"
\"x%5E2%2B4x\"Partial quotient times divisor
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\"x\"
\"x%2B4\"\"x%5E2%2B2x-36\"
\"x%5E2%2B4x\"
  \"-2x-36\"Subtract and bring down next term
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\"x-2\"Divide by first term of divisor again
\"x%2B4\"\"x%5E2%2B2x-36\"
\"x%5E2%2B4x\"
  \"-2x-36\"
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\"x-2\"
\"x%2B4\"\"x%5E2%2B2x-36\"
\"x%5E2%2B4x\"
  \"-2x-36\"
  \"-2x-8\"Multiply by new quotient term
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\"x-2\"
\"x%2B4\"\"x%5E2%2B2x-36\"
\"x%5E2%2B4x\"
  \"-2x-36\"
  \"-2x-8\"
    \"-28\"Subtract leaving remainder
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\n" ); document.write( "\n" ); document.write( "So: \"%28x%5E2%2B2x-36%29%2F%28x%2B4%29=%28x-2%29%2B%28-28%29%2F%28x%2B4%29\" \n" ); document.write( "
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