document.write( "Question 122289This question is from textbook Mechanics I
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document.write( ": I didnt know what topic this stuff came under, :( so i thought proof maybe....the closest i can find, its a mechanics question.\r
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document.write( "11. A parcel of mass 60kg is released from rest on a smooth plane inclined at arcsin 0.6 (3/5) to the horizontal. Find the velocity of the parcel when it has travelled 5m down the slope.\r
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document.write( "I cant do it, can some one help?\r
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document.write( "What i personally did was,\r
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document.write( "invsin0.6 = 37, Sin37*9.81*60 = 354 approx.\r
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document.write( "So Acceleration down the slope is 354ms-2, \r
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document.write( "v squared = u sqaured + 2as,\r
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document.write( "so, velocity squared therefore =, 2 * 354 * 5 = 3540, root that = velocity, =59.5...\r
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document.write( "but the answer is 7.67 :( Please help? with details of how to do, thanks. \n" );
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Algebra.Com's Answer #89853 by scott8148(6628)![]() ![]() You can put this solution on YOUR website! not sure why you included the mass in the calculation? __ there is no mention of friction...\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the acceleration along the incline is g*sin(a) \n" ); document.write( "__ where a is the angle of inclination and g is the gravitational acceleration\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "using .6g as the acceleration will give you the proper result\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the rest of your work is fine \n" ); document.write( " |