document.write( "Question 122359This question is from textbook texas algebra 1
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\n" ); document.write( "\n" ); document.write( "find the slope of a line perpendicular to the graph of each equation.
\n" ); document.write( "20. y= -3x
\n" ); document.write( "24. y= -8\r
\n" ); document.write( "\n" ); document.write( "Write and equation for the line that is perpendicular to the given line and that passes through the given point.
\n" ); document.write( "26. y= x-3; (4,6)\r
\n" ); document.write( "\n" ); document.write( "Hope you reply soon. this is the last chapter for this lesson! Thanks, much appreciated :D
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Algebra.Com's Answer #89846 by checkley71(8403)\"\" \"About 
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20) Y=-3 HAS A SLOPE OF -3 THEREFORE A PERPENDICULAR LINE SLOPE=1/3.
\n" ); document.write( "24) Y=-8 HAS A SLOPE OF -8 THEREFORE A PERPENDICULAR LINE SLOPE=1/8.
\n" ); document.write( "26) Y=X-3 HAS A SLOPE OF 1 THEREFORE A PERPENDICULAR LINE SLOPE=-1.
\n" ); document.write( "6=-1*4+b
\n" ); document.write( "6=-4+b
\n" ); document.write( "b=6+4
\n" ); document.write( "b=10 THEREFORE THIS EQUATION IS:
\n" ); document.write( "Y=-X+10.
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