document.write( "Question 122324: I need to write the equation of the line that is perpendicular to the given line and passes through the given point. I am stuck and confused.\r
\n" ); document.write( "\n" ); document.write( "Here is the equation
\n" ); document.write( "2x-4y=8 (-3,1)\r
\n" ); document.write( "\n" ); document.write( "This is what I have
\n" ); document.write( "2x-4y=8
\n" ); document.write( " -4y=-2x+8
\n" ); document.write( " /-4=/-4/-4
\n" ); document.write( " y=1/2x-2\r
\n" ); document.write( "\n" ); document.write( "y=mx+b
\n" ); document.write( "1=-1/2(-3)+b
\n" ); document.write( "1=3/2+b
\n" ); document.write( "1-3/2=3/2+b-3/2
\n" ); document.write( "1/2=b\r
\n" ); document.write( "\n" ); document.write( "y=-2x+1/2
\n" ); document.write( "

Algebra.Com's Answer #89833 by kwobsi(2)\"\" \"About 
You can put this solution on YOUR website!
first find the gradient m from the equation
\n" ); document.write( "2x-4y=8
\n" ); document.write( "that is by making y the subject
\n" ); document.write( "y = 1/2x - 2
\n" ); document.write( "from y=mx+b
\n" ); document.write( "m = 1/2
\n" ); document.write( "x1 and y1 represents the points -3 and 1 respectively
\n" ); document.write( "from formular (x-x1)=m(y-y1)
\n" ); document.write( "we have (x+3)=1/2(y-1)
\n" ); document.write( "2x+6=y-1
\n" ); document.write( "2x+7=y is the equation of the line
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