document.write( "Question 122324: I need to write the equation of the line that is perpendicular to the given line and passes through the given point. I am stuck and confused.\r
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document.write( "Here is the equation
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document.write( "2x-4y=8 (-3,1)\r
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document.write( "This is what I have
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document.write( "2x-4y=8
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document.write( " -4y=-2x+8
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document.write( " /-4=/-4/-4
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document.write( " y=1/2x-2\r
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document.write( "y=mx+b
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document.write( "1=-1/2(-3)+b
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document.write( "1=3/2+b
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document.write( "1-3/2=3/2+b-3/2
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document.write( "1/2=b\r
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document.write( "y=-2x+1/2 \n" );
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Algebra.Com's Answer #89833 by kwobsi(2)![]() ![]() ![]() You can put this solution on YOUR website! first find the gradient m from the equation \n" ); document.write( "2x-4y=8 \n" ); document.write( "that is by making y the subject \n" ); document.write( "y = 1/2x - 2 \n" ); document.write( "from y=mx+b \n" ); document.write( "m = 1/2 \n" ); document.write( "x1 and y1 represents the points -3 and 1 respectively \n" ); document.write( "from formular (x-x1)=m(y-y1) \n" ); document.write( "we have (x+3)=1/2(y-1) \n" ); document.write( "2x+6=y-1 \n" ); document.write( "2x+7=y is the equation of the line \n" ); document.write( " \n" ); document.write( " |