document.write( "Question 122332: find three consecutive integers such that 5 times the sum of the first and third is 14 greater than 8 times the second. \n" ); document.write( "
Algebra.Com's Answer #89822 by solver91311(24713)\"\" \"About 
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document.write( "Let the first of three consecutive integers be \"n\".\r\n" );
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document.write( "Then the second is \"n%2B1\" and the third is \"n%2B2\".\r\n" );
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document.write( "The sum of the first and third is \"n%2B%28n%2B2%29\" or \"2n%2B2\".\r\n" );
document.write( "5 times that is \"5%282n%2B2%29=10n%2B10\"\r\n" );
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document.write( "This quantity is (meaning equals) 14 greater than 8 times the second.\r\n" );
document.write( "8 times the second is \"8%28n%2B1%29=8n%2B8\", and 14 more than that is\r\n" );
document.write( "\"8n%2B8%2B14=8n%2B22\", so we can write:\r\n" );
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document.write( "\"10n%2B10=8n%2B22\"\r\n" );
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document.write( "Add \"-8n\" to both sides\r\n" );
document.write( "\"10n-8n%2B10=8n-8n%2B22\"\r\n" );
document.write( "\"2n%2B10=22\"\r\n" );
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document.write( "Add \"-10\" to both sides\r\n" );
document.write( "\"2n%2B10-10=22-10\"\r\n" );
document.write( "\"2n=12\"\r\n" );
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document.write( "Multiply by \"1%2F2\"\r\n" );
document.write( "\"%281%2F2%292n=%281%2F2%2912\"\r\n" );
document.write( "\"n=6\"\r\n" );
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document.write( "Therefore the first number is \"6\", the second is \"7\" and the third is \"8\".\r\n" );
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document.write( "Check the answer\r\n" );
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document.write( "6 plus 8 = 14.   5 times 14 = 70\r\n" );
document.write( "8 times 7 = 56.  56 plus 14 = 70\r\n" );
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