document.write( "Question 122319: I need to write the equation of the line that is perpendicular to the given line and passes through the given point. I am stuck and confused.\r
\n" ); document.write( "\n" ); document.write( "Here is the equation
\n" ); document.write( "y=-2x-1 (2,6)\r
\n" ); document.write( "\n" ); document.write( "Here is what I have
\n" ); document.write( "y=mx+b
\n" ); document.write( "6=-2(2)+b
\n" ); document.write( "6=-4+b
\n" ); document.write( "6+4=-4+b+4
\n" ); document.write( "10=b\r
\n" ); document.write( "\n" ); document.write( "y=1/2x+10 \n" ); document.write( "
Algebra.Com's Answer #89813 by checkley71(8403)\"\" \"About 
You can put this solution on YOUR website!
Y=-2X-1 (RED LINE)FOR A LINE TO BE PERPENDICULAR IT HAS A SLOPE EQUAL TO THE NEGATIVE RECIPRICAL OF THIS SLOPE.
\n" ); document.write( "THUS THE SLOPE OF THE PERPENDICULAR LINE =1/2.
\n" ); document.write( "USING THE LINE FORMULA:
\n" ); document.write( "Y=mX+b & SUBSTITUTION THE SLOPE VALUE=1/2 & USING THE POINT VALUES (2,6) WE SOLVE FOR b.
\n" ); document.write( "6=1/2*2+b
\n" ); document.write( "6=-+B
\n" ); document.write( "b=6-1
\n" ); document.write( "b=5 FOR THE Y INTERCEPT.
\n" ); document.write( "THUS THE EQUATION IS:
\n" ); document.write( "Y=X/2+5 (GREEN LINE)
\n" ); document.write( "\"+graph%28+300%2C+300%2C+-6%2C+6%2C+-6%2C+6%2C+y+=+-2x+-1%2C+y+=+x%2F2+%2B5%29+\" (graph 300x300 pixels, x from -6 to 6, y from -6 to 6, of TWO functions y = -2x -1 and y = x/2 +5).
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