document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=122264>Question 122264</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a 15 foot ladder is placed against a wall at an angle of 65 degres with the ground. how far away is the bottom of the ladder from the wall to the nearest tenth? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #89812 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrapro18><B>algebrapro18(249)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrapro18><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=89812\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Here you going to want to use cosine.  <br>\r<BR>\n" );
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document.write( "the base of the triangle created by the latter and the wall is x and the hypontenuse is 15 feet so that sets up this trig ratio:<br>\r<BR>\n" );
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document.write( "cos 65 = x/15 <br>\r<BR>\n" );
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document.write( "now we just need to solve for x<br>\r<BR>\n" );
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document.write( "cos 65 = x/15 --> multiply both sides by 15<BR>\n" );
document.write( "15 cos(65) = x --> approximate the value of x<BR>\n" );
document.write( "6.3 = x </SPAN>\n" );
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