document.write( "Question 122309This question is from textbook Finite Mathematics an Applied Approach
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document.write( ": The length of fence required to enclose a rectangular field is 3000 meters. What are the dimensions of the field if the difference between its length and width is 50 meters? \n" );
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Algebra.Com's Answer #89796 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! 2x+2(x+50)=3000 \n" ); document.write( "2x+2x+100=3000 \n" ); document.write( "4x=3000-100 \n" ); document.write( "4x=2900 \n" ); document.write( "x=2900/4 \n" ); document.write( "x=725 for the length. \n" ); document.write( "x+50=775 for the width. \n" ); document.write( "proof \n" ); document.write( "2*725+2*775=3000 \n" ); document.write( "1450+1550=3000 \n" ); document.write( "3000=3000 \n" ); document.write( " |