document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=122151>Question 122151</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Draw the appropriate graphs\r<BR>\n" );
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document.write( "A small firm produces both AM amd AM/FM car radios.  The AM radios take 15 h to produce, and the AM/FM radios take 20 h.  The number of production hours is limited to 300 h per week.  The plant's capacity is limited to ta total of 18 radios per week, and existing orders require that at least 4 AM radios and at least 3 AM/FM radios be produced per week.  Write a system of inequalities representing this situation.  Then, draw a graph of the feasible region given these conditions, in which x is the number of AM radios and y the number of AM/FM radios. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #89772 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=89772\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This same problem came up a few weeks ago. This is what I submitted then. Perhaps it will help you'<BR>\n" );
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document.write( "A small firm produces both AM and AM/FM car radios. The AM radios take 15 h to produce, and the AM/FM radios take 20 h. The number of production hours is limited to 300 h per week. The plant's capacity is limited to a total of 18 radios per week, and existing orders require that at least 4 AM radios and at least 3 AM/FM radios be produced per week. Write a system of inequalities representing this situation. Then, draw a graph of the feasible region given these conditions, in which X is the number of AM radios and Y is the number of AM/FM radios. <BR>\n" );
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document.write( "Let x = number of AM radios; let y = number of AM/FM radios<BR>\n" );
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document.write( "The production hour constraint:<BR>\n" );
document.write( "15x + 20y =< 300<BR>\n" );
document.write( "Arrange in general form to plot the graph<BR>\n" );
document.write( "20y =< 300 - 15x<BR>\n" );
document.write( "y =< 300/20 - (15/20)x<BR>\n" );
document.write( "y =< 15 - .75x, use this to plot the production hr graph (Purple line)<BR>\n" );
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document.write( "Plant's capacity constraint:<BR>\n" );
document.write( "x + y =< 18<BR>\n" );
document.write( "y =< 18 - x, plot this graph also (Green line)<BR>\n" );
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document.write( "Min AM radio production constraint:<BR>\n" );
document.write( "x => 4<BR>\n" );
document.write( "This will be a vertical line going thru the x axis at +4<BR>\n" );
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document.write( "Min AM/FM radio production constraint <BR>\n" );
document.write( "y => 3<BR>\n" );
document.write( "This will be a horizontal line going thru the y axis at +3, (Dark blue line)<BR>\n" );
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document.write( "Here is the graph as presented by these equations. <BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+graph%28+300%2C+200%2C+-5%2C+25%2C+-5%2C+25%2C+15-.75x%2C+18-x%2C3%2C+60000%28x-4%29%29+ ALIGN=MIDDLE  ALT=\"+graph%28+300%2C+200%2C+-5%2C+25%2C+-5%2C+25%2C+15-.75x%2C+18-x%2C3%2C+60000%28x-4%29%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "The feasibility region:<BR>\n" );
document.write( " 1. At or below the purple or green line, whichever is lowest<BR>\n" );
document.write( " 2. At or above the horizontal line<BR>\n" );
document.write( " 3. At or to the right of the vertical line<BR>\n" );
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document.write( "How about this, did it all make some sense to you? </SPAN>\n" );
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