document.write( "Question 122123: Use the quadratic formula to solve.\r
\n" ); document.write( "\n" ); document.write( "2x squared - 5x = 3 \n" ); document.write( "
Algebra.Com's Answer #89746 by madhan_math(34)\"\" \"About 
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Given equation is 2x^2-5x=3
\n" ); document.write( " 2x^2-5x-3=0
\n" ); document.write( " Now the coefficient of x^2 and constant multiplying, we get
\n" ); document.write( " -6.
\n" ); document.write( " Then, we find two numbers that numbers will be added we get -5(the coefficient of x)and multiply that numbers will become -6.
\n" ); document.write( " Therefore, that numbers are -6, 1
\n" ); document.write( " Now the given equation becomes 2x^2-6x+x-3=0.
\n" ); document.write( " (We take common number from first two variables.)
\n" ); document.write( " i.e., 2x(x-3) + 1(x-3)=0
\n" ); document.write( " i.e., (2x+1)=0,(x-3)=0 are the factors of the given eqn.
\n" ); document.write( " Hence x=-1/2 and x=3.
\n" ); document.write( " (OR)
\n" ); document.write( " The problem also solve by using the formula\r
\n" ); document.write( "\n" ); document.write( "http://www.algebra.com/cgi-bin/plot-formula.mpl?expression=x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29&x=0003\r
\n" ); document.write( "\n" ); document.write( " In this equation a=2, b=-5, c=-3 and substitute these values in that formulae we will get x=-1/2 and x=3.
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