document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=122243>Question 122243</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Algebraically solve: 70=6+8(^3x-1) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #89744 by </B><A HREF=/tutors/aboutme.mpl?userid=jainenderkapoor><B>jainenderkapoor(61)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jainenderkapoor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jainenderkapoor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=89744\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Algebraically solve: 70=6+8(^3x-1)\r<BR>\n" );
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document.write( "70 - 6 = 8^(3x -1)<BR>\n" );
document.write( "64 = 8^(3x -1)<BR>\n" );
document.write( "8^2 = 8^(3x -1)<BR>\n" );
document.write( "Comparing both sides we get --  exponents to be same\r<BR>\n" );
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document.write( "2 = 3x - 1<BR>\n" );
document.write( "2 + 1 = 3x<BR>\n" );
document.write( "3 = 3x<BR>\n" );
document.write( "x = 3/3 = 1\r<BR>\n" );
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document.write( "Hope the solution is clear to you. If you need any help, I am available for Online Tutoring at very reasonable rates. My email is is jainenderkapoor@gmail.com </SPAN>\n" );
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