document.write( "Question 122125: Solve using the quadratic formula\r
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\n" ); document.write( "\n" ); document.write( "3x squared - 2x + 1 = 0
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Algebra.Com's Answer #89741 by bucky(2189)\"\" \"About 
You can put this solution on YOUR website!
Given the equation:
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\n" ); document.write( "\"3x%5E2-2x%2B1=0\"
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\n" ); document.write( "To solve this using the quadratic formula, begin by comparing the given equation to the
\n" ); document.write( "standard quadratic form of:
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\n" ); document.write( "\"ax%5E2%2Bbx%2Bc+=+0\"
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\n" ); document.write( "If you compare them term-by-term, you see that \"a\" which is the multiplier of the x-squared must
\n" ); document.write( "be 3. And b which is the multiplier of the x must be -2. And finally, c which is the constant
\n" ); document.write( "must be +1. So in solving this equation using the quadratic formula, you use a = +3, b = -2, and
\n" ); document.write( "c = +1.
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\n" ); document.write( "The quadratic formula says that any quadratic equation of the form:
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\n" ); document.write( "\"ax%5E2%2Bbx%2Bc+=+0\"
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\n" ); document.write( "has for its roots the values of x determined by using the equation:
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\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
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\n" ); document.write( "So all that has to be done to find the values of x is to substitute the appropriate
\n" ); document.write( "values of a, b, and c into this equation for x.
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\n" ); document.write( "Using the values of a, b, and c as identified above for this problem, results in the equation
\n" ); document.write( "for x becoming:
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\n" ); document.write( "The -(-2) becomes just +2. And the denominator of 2*3 becomes 6. These two changes result
\n" ); document.write( "in the equation for x being simplified to:
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\n" ); document.write( "\"x+=+%282+%2B-+sqrt%28+%28-2%29%5E2-4%2A3%2A1+%29%29%2F6\"
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\n" ); document.write( "Next work on simplifying the quantity within the radical sign. Squaring -2 results in
\n" ); document.write( "+4 and multiplying -4 times 3 times 1 results in -12. Substituting these results under the
\n" ); document.write( "radical simplifies the equation for x to:
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\n" ); document.write( "\"x+=+%282+%2B-+sqrt%284-12%29%29%2F6+=+%282+%2B-+sqrt%28-8%29%29%2F6+\"
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\n" ); document.write( "Notice that the term inside the radical sign is negative. This tells you several things. First
\n" ); document.write( "it tells you that the graph of the quadratic equation you were given does not cross or touch
\n" ); document.write( "the x-axis. And it tells you that the values for x contain an imaginary part.
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\n" ); document.write( "Lets concentrate now on what that imaginary part is by just working on the part of the answer
\n" ); document.write( "that involves the radical:
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\n" ); document.write( "\"sqrt%28-8%29\"
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\n" ); document.write( "Using the rules of square roots we can simplify this to:
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\n" ); document.write( "\"sqrt%28-8%29+=+sqrt%284%2A-2%29+=+sqrt%284%29%2Asqrt%28-2%29+=+2%2Asqrt%28-2%29\"
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\n" ); document.write( "Next define \"i%5E2+=+-1\"
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\n" ); document.write( "Substituting \"i%5E2\" into the radical (in place of the -1 that multiplies the 2}}} and applying
\n" ); document.write( "some rules of radical simplification results in the radical term becoming:
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\n" ); document.write( "Going all the way back to the equation for x and substituting this result for the radical
\n" ); document.write( "results in:
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\n" ); document.write( "\"x+=+%282+%2B-+sqrt%28-8%29%29%2F6++=+%282+%2B-+%282%2Asqrt%282%29%29%2Ai%29%2F6\"
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\n" ); document.write( "Notice that 2 is a common factor of all terms in the numerator and also of the denominator.
\n" ); document.write( "Therefore, the factor 2 can be divided into the numerator and denominator and this reduces
\n" ); document.write( "the answers to:
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\n" ); document.write( "\"x+=+%282+%2B-+%282%2Asqrt%282%29%29%2Ai%29%2F6+=+%281+%2B-+%28sqrt%282%29%29%2Ai%29%2F3\"
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\n" ); document.write( "Hope that you can track all the math here so that you can understand where the answer comes
\n" ); document.write( "from. And I hope this gives you a little more insight into solving for x in quadratic
\n" ); document.write( "equations that have complex roots.
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