document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=122119>Question 122119</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I solve 3+ (square root of) x^2-8x = 0  ?  Please note I do not know how to put the square root sign, but x^2-8x is under the square sign. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #89659 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=89659\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> subtracting 3 __ sqrt(x^2-8x)=-3\r<BR>\n" );
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document.write( "squaring __ x^2-8x=9\r<BR>\n" );
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document.write( "subtracting 9 __ x^2-8x-9=0\r<BR>\n" );
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document.write( "factoring __ (x-9)(x+1)=0 </SPAN>\n" );
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