document.write( "Question 122110This question is from textbook Algebra: structure and method: Book 1
\n" ); document.write( ": Erica hiked up a mountain trail at 3 km/h and returned at 4 km/h. The entire trip took 5 hours and 10 minutes, including the 1/2 hour she spent resting. How long was the trail? PLEASE HELP!!!!!!! The answer is 8 km, but I don't know how to get there. HELP!!!!!!!!! \n" ); document.write( "
Algebra.Com's Answer #89654 by solver91311(24713)\"\" \"About 
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document.write( "Start with distance = rate times time, or \"d=rt\".  We can safely presume\r\n" );
document.write( "that the distance up the hill is the same as the distance back down the hill.\r\n" );
document.write( "Let's say that \"d\" is the distance up or down the hill, \"r%5Bu%5D\" is the\r\n" );
document.write( "rate up the hill (given as 3 km/h), \"r%5Bd%5D\" is the rate down the hill (given\r\n" );
document.write( "as 4 km/h), and \"t%5Bu%5D\" and \"t%5Bd%5D\" are the times she took going up and\r\n" );
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document.write( "We know she rested for 30 minutes, so she spent 5 hrs 10 min minus 30 minutes\r\n" );
document.write( "or 4 hrs 40 min actually hiking.  4 hr 40 min is 4 and 2/3 or \"14%2F3\" hours.\r\n" );
document.write( "Since \"t%5Bu%5D%2Bt%5Bd%5D=14%2F3\", we can say that \"t%5Bd%5D=14%2F3-t%5Bu%5D\"\r\n" );
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document.write( "Using \"d=rt\", we can say that the distance up the hill is \"d=3t%5Bu%5D\",\r\n" );
document.write( "and the distance downhill is \"d=4t%5Bd%5D\", but since we have established that\r\n" );
document.write( "\"t%5Bd%5D=14%2F3-t%5Bu%5D\", we can substitute and write \"d=4%2814%2F3-t%5Bu%5D%29\".\r\n" );
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document.write( "Now we have two different expressions for the same distance, so we can set\r\n" );
document.write( "them equal to each other:\r\n" );
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document.write( "\"3t%5Bu%5D=4%2814%2F3-t%5Bu%5D%29\"\r\n" );
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document.write( "Next, solve for \"t%5Bu%5D\"\r\n" );
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document.write( "\"3t%5Bu%5D=56%2F3-4t%5Bu%5D\"\r\n" );
document.write( "\"7t%5Bu%5D=56%2F3\"\r\n" );
document.write( "\"t%5Bu%5D=8%2F3\"\r\n" );
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document.write( "So the time to go uphill is \"8%2F3\" hour or 2 and 2/3 hour.\r\n" );
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document.write( "Since she travelled at 3 km/hr uphill, \"d=3%288%2F3%29=8\" km.\r\n" );
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document.write( "Check the answer\r\n" );
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document.write( "If the time uphill was 8/3, and the total time was 14/3, the time downhill\r\n" );
document.write( "must have been 6/3, or 2 hours.  2 hours times 4 km/hr equals 8 km.\r\n" );
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document.write( "Answer checks.\r\n" );
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