document.write( "Question 122076: Find the value of r so that the line through (-4,3) and (r, -3) has a slope of 2/3. \n" ); document.write( "
Algebra.Com's Answer #89613 by ankor@dixie-net.com(22740)\"\" \"About 
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Find the value of r so that the line through (-4,3) and (r, -3) has a slope of 2/3.
\n" ); document.write( ":
\n" ); document.write( "Using the slope formula; \"%28y2-y1%29%2F%28x2-x1%29\" = m
\n" ); document.write( "Assign the values as follows:
\n" ); document.write( "x1 = -4; y1 = 3
\n" ); document.write( "x2 = r; y2 = -3
\n" ); document.write( "m = \"2%2F3\"
\n" ); document.write( ":
\n" ); document.write( "\"%28-3+-+3%29%2F%28r+-+%28-4%29%29\" = \"2%2F3\"
\n" ); document.write( "\"%28-6%29%2F%28%28r%2B4%29%29\" = \"2%2F3\"
\n" ); document.write( "Cross multiply
\n" ); document.write( ":
\n" ); document.write( "2(r+4) = -6(3)
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\n" ); document.write( "2r + 8 = -18
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\n" ); document.write( "2r = -18 - 8
\n" ); document.write( ":
\n" ); document.write( "r = \"%28-26%29%2F2\"
\n" ); document.write( "r = -13
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\n" ); document.write( ":
\n" ); document.write( "Check by finding the slope using x2 = -13
\n" ); document.write( "\"%28-6%29%2F%28%28-13%2B4%29%29\" =
\n" ); document.write( "\"%28-6%29%2F%28-9%29\" = +\"2%2F3\"
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