document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=18658>Question 18658</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Aaron is twice as old as Jack. The sum of their ages three years ago was 45 years. How old are they now?\r<BR>\n" );
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document.write( "My problem is when I get the solution, the ages are backwards.\r<BR>\n" );
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document.write( "Now Aaron = 2 Now Jack<BR>\n" );
document.write( "(Now Aaron - 3) + (Now Jack -3) = 45<BR>\n" );
document.write( "Now Aaron + Now Jack = 51<BR>\n" );
document.write( "Now Jack = 51 - Now Aaron<BR>\n" );
document.write( "Substitute-<BR>\n" );
document.write( "Now Aaron = 2(51 - Now Aaron)<BR>\n" );
document.write( "Now Aaron = 51 - 2 now Aaron<BR>\n" );
document.write( "3 Now Aaron = 51<BR>\n" );
document.write( "Aaron = 17<BR>\n" );
document.write( "Jack = 34\r<BR>\n" );
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document.write( "But Aaron is supposed to be twice Jacks age not half it. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #8961 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=8961\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Try this.\r<BR>\n" );
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document.write( "A = Aaron's age now.<BR>\n" );
document.write( "J = Jack's age now.<BR>\n" );
document.write( "Write two equations from the problem description.\r<BR>\n" );
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document.write( "A = 2J Aaron is twice Jack's age.<BR>\n" );
document.write( "(A-3) + (J-3) = 45 The sum of their ages 3 years ago = 45 Simplify.<BR>\n" );
document.write( "A + J - 6 = 45  Add 6 to both sides.<BR>\n" );
document.write( "A + J = 51 Substitute A = 2J<BR>\n" );
document.write( "2J + J = 51<BR>\n" );
document.write( "3J = 51 Divide both sides by 3.<BR>\n" );
document.write( "J = 17 years.<BR>\n" );
document.write( "A = 2J = 2(17) = 34 years. </SPAN>\n" );
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