document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=122009>Question 122009</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0534404693/algebrahomeworkh>algebra and trigonometry with analiytic geometry</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\">  British sterling silver is a copper-silver alloy that is 7.5% copper by weight. How many grams of pure copper and how many grams of British sterling silver should be used to prepare 244 grams of a copper-silver alloy that is 13% copper by weight?\r<BR>\n" );
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document.write( "Please round the answers to the nearest tenth.\r<BR>\n" );
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document.write( "British sterling silver: g\r<BR>\n" );
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document.write( "pure copper: g<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #89609 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=89609\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  British sterling silver is a copper-silver alloy that is 7.5% copper by weight. How many grams of pure copper and how many grams of British sterling silver should be used to prepare 244 grams of a copper-silver alloy that is 13% copper by weight?<BR>\n" );
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document.write( "Please round the answers to the nearest tenth.<BR>\n" );
document.write( "British sterling silver: g<BR>\n" );
document.write( "pure copper: g:<BR>\n" );
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document.write( "Let x = no. of grams of British sterling silver (which is 7.5% copper) required<BR>\n" );
document.write( "Then<BR>\n" );
document.write( "(244-x) = no. of grams of pure copper required to make 13% alloy<BR>\n" );
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document.write( "Write an equation based on the % copper<BR>\n" );
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document.write( ".075x + 1.0(244-x) = .13(244)<BR>\n" );
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document.write( ".075x + 244 - 1x = 31.72<BR>\n" );
document.write( ".075x - 1x = 31.72 - 244<BR>\n" );
document.write( "-.925x =  -212.28<BR>\n" );
document.write( "x = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28-212.28%29%2F%28-.925%29 ALIGN=MIDDLE  ALT=\"%28-212.28%29%2F%28-.925%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "x = 229.5 grams Br Sterling Silver<BR>\n" );
document.write( "Then<BR>\n" );
document.write( "244 - 229.5 = 14.5 grams of pure copper<BR>\n" );
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document.write( "Check solution based on the copper per cent<BR>\n" );
document.write( ".075(229.5) + 14.5 = .13(244)<BR>\n" );
document.write( "17.2125 + 14.5 = 31.72<BR>\n" );
document.write( "    31.7125 ~ 31.72<BR>\n" );
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document.write( "Could you follow this OK? Any questions?<BR>\n" );
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