document.write( "Question 122036: please help me slove this problem \r
\n" ); document.write( "\n" ); document.write( "Slove the problem. Find out how long it takes a $3000 investment to double if it is invested at 8% compounded semiannually. Round to the nearest tenth of a year. Use the formula \r
\n" ); document.write( "\n" ); document.write( "A=P(1+r/n)^nt\r
\n" ); document.write( "\n" ); document.write( "possible anwsers\r
\n" ); document.write( "\n" ); document.write( "1.) 8.8 years
\n" ); document.write( "2.) 9.2 years
\n" ); document.write( "3.) 9 years
\n" ); document.write( "4.) 8.6 years \r
\n" ); document.write( "\n" ); document.write( "thank you for your help
\n" ); document.write( "

Algebra.Com's Answer #89586 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
\"P+=+3000\"
\n" ); document.write( "\"r+=+.08\"
\n" ); document.write( "\"n+=+2\" (\"n\" is the number of times per year interest is compounded)
\n" ); document.write( "\"A+=+6000\" (\"A\" is the amount after \"t\" years. The problem
\n" ); document.write( "wants to know what \"t\" is when \"A+=+2P\")
\n" ); document.write( "\"A+=+P%281+%2B+r%2Fn%29%5Ent\"
\n" ); document.write( "\"6000+=+3000%281+%2B+.08%2F2%29%5E%282t%29\"
\n" ); document.write( "divide both sides by \"3000\"
\n" ); document.write( "\"2+=+%281+%2B+.04%29%5E%282t%29\"
\n" ); document.write( "\"2+=+1.04%5E%282t%29\"
\n" ); document.write( "Take the log to base 10 of both sides
\n" ); document.write( "\"log%282%29+=+2t%2Alog%281.04%29\"
\n" ); document.write( "\".30103+=+2t%2A.01703\"
\n" ); document.write( "\"t+=+.30103+%2F+.03406\"
\n" ); document.write( "\"t+=+8.8382\" years
\n" ); document.write( "That's approximately (1) 8.8
\n" ); document.write( "This is \"8\" years + \".8382%2A12+=+10.059\" months
\n" ); document.write( "And this is \"8\" years, \"10\" months \".059%2A30+=+2\" day
\n" ); document.write( "The answer is \"8\" years \"10\" months \"2\" day
\n" ); document.write( "Unless I made a mistake, that is.
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