document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=121883>Question 121883</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the linear system:\r<BR>\n" );
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document.write( "y=2x+1<BR>\n" );
document.write( "-2x+3y=-9\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #89583 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=89583\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> substituting the value of y from the first equation into the second __ -2x+3(2x+1)=-9\r<BR>\n" );
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document.write( "-2x+6x+3=-9 __ 4x=-12 __ x=-3\r<BR>\n" );
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document.write( "y=2(-3)+1 __ y=-5 </SPAN>\n" );
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