document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=121994>Question 121994</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have a page size of 210mm X 297mm. I need to place a logo on the page which covers 7% of the total area of the page. How do I work out the dimensions of the logo? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #89575 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=89575\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> TOTAL ARE OF THE PAGE IS:<BR>\n" );
document.write( "210*297=62,370 MM^2<BR>\n" );
document.write( "7% OF THIS AREA IS:<BR>\n" );
document.write( ".07*62,370~4,366 MM^2<BR>\n" );
document.write( "ANY 2 DIMENTIONS (LESS THAN 297) WHEN MULTIPLIED TOGETHER THAT EQUALS 4,365.9 MM^2 IS AN ANSWER.<BR>\n" );
document.write( "100*X=4,366<BR>\n" );
document.write( "X=4,366/100<BR>\n" );
document.write( "X=43.66 IS THE SECOND DIMENTION.<BR>\n" );
document.write( "100x43.66=4366 IS ONE ANSWER.<BR>\n" );
document.write( "IF YOU WANT THE PICTURE TO BE PROPORTIONAL TO THE PAGE THEN:<BR>\n" );
document.write( "(297-2X)(210-2X)=4366<BR>\n" );
document.write( "62370-420X-594X+4X^2=4366<BR>\n" );
document.write( "4X^2-1014X+62370-4366=0<BR>\n" );
document.write( "4X^2-1014X+58004=0<BR>\n" );
document.write( "USING THE QUADRATIC EQUATION WE GET:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=TOTAL+ARE+OF+THE+PAGE+IS%3A%0D%0A210%2A297=62%2C370+MM%5E2%0D%0A7%25+OF+THIS+AREA+IS%3A%0D%0A.07%2A62%2C370%7E4%2C366+MM%5E2%0D%0AANY+2+DIMENTIONS+%28LESS+THAN+297%29+WHEN+MULTIPLIED+TOGETHER+THAT+EQUALS+4%2C365.9+MM%5E2+IS+AN+ANSWER.%0D%0A100%2AX=4%2C366%0D%0AX=4%2C366%2F100%0D%0AX=43.66+IS+THE+SECOND+DIMENTION.%0D%0A100x43.66=4366+IS+ONE+ANSWER.%0D%0AIF+YOU+WANT+THE+PICTURE+TO+BE+PROPORTIONAL+TO+THE+PAGE+THEN%3A%0D%0A%28297-2X%29%28210-2X%29=4366%0D%0A62370-420X-594X%2B4X%5E2=4366%0D%0A4X%5E2-1014X%2B62370-4366=0%0D%0A4X%5E2-1014X%2B58004=0%0D%0AUSING+THE+QUADRATIC+EQUATION+WE+GET%3A%0D%0A ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" >x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}<BR>\n" );
document.write( "X=166.3 & 87.2<BR>\n" );
document.write( "2*166.2=332.4 WHICH IS MORE THAN THE WIDTH & LENGTH. THUS NOT AN ANSWER.<BR>\n" );
document.write( "2*87.2=174.4 WHICH IS THE SUM OF THE 2 BORDERS.<BR>\n" );
document.write( "THUS WE HAVE THE DIMENTIONS OF:<BR>\n" );
document.write( "297-174.4=122.6<BR>\n" );
document.write( "210-174.4=35.6<BR>\n" );
document.write( "122.6*35.6~4366<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );