document.write( "Question 121989: I am not sure if I am doing this right. Solve for K.\r
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document.write( " a/b=b/a+1/k
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document.write( " (bak) a/b=(bak)b/a+1/k(bak)
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document.write( " a^2k=b^2k+ba
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document.write( " a^2k-b^2k=ba
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document.write( " k(a^2-b^2)=ab
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document.write( " k=ab/a^2-b^2 \n" );
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Algebra.Com's Answer #89561 by oscargut(2103)![]() ![]() You can put this solution on YOUR website! Yes you are right, \r \n" ); document.write( "\n" ); document.write( "obs: a^2-b^2 must be not equal to 0\r \n" ); document.write( "\n" ); document.write( "Other way\r \n" ); document.write( "\n" ); document.write( "a/b=b/a+1/k then (a/b)-(b/a)=1/k then (a^2-b^2)/ab = 1/k \n" ); document.write( "then k= (ab)/(a^2-b^2) \n" ); document.write( " |