document.write( "Question 121989: I am not sure if I am doing this right. Solve for K.\r
\n" ); document.write( "\n" ); document.write( " a/b=b/a+1/k
\n" ); document.write( " (bak) a/b=(bak)b/a+1/k(bak)
\n" ); document.write( " a^2k=b^2k+ba
\n" ); document.write( " a^2k-b^2k=ba
\n" ); document.write( " k(a^2-b^2)=ab
\n" ); document.write( " k=ab/a^2-b^2
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Algebra.Com's Answer #89561 by oscargut(2103)\"\" \"About 
You can put this solution on YOUR website!
Yes you are right, \r
\n" ); document.write( "\n" ); document.write( "obs: a^2-b^2 must be not equal to 0\r
\n" ); document.write( "\n" ); document.write( "Other way\r
\n" ); document.write( "\n" ); document.write( "a/b=b/a+1/k then (a/b)-(b/a)=1/k then (a^2-b^2)/ab = 1/k
\n" ); document.write( "then k= (ab)/(a^2-b^2)
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