document.write( "Question 121913: Name the vertex for the parabol with equation
\n" ); document.write( "y= 3x^2-12x+16
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Algebra.Com's Answer #89531 by jim_thompson5910(35256)\"\" \"About 
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To find the vertex, we first need to find the axis of symmetry (ie the x-coordinate of the vertex)\r
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\n" ); document.write( "\n" ); document.write( "\"x=-b%2F%282a%29\"\r
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\n" ); document.write( "\n" ); document.write( "From the equation \"y=3x%5E2-12x%2B16\" we can see that a=3 and b=-12\r
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\n" ); document.write( "\n" ); document.write( "\"x=%28--12%29%2F%282%2A3%29\" Plug in b=-12 and a=3\r
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\n" ); document.write( "\n" ); document.write( "\"x=12%2F%282%2A3%29\" Negate -12 to get 12\r
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\n" ); document.write( "\n" ); document.write( "\"x=%2812%29%2F6\" Multiply 2 and 3 to get 6\r
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\n" ); document.write( "\n" ); document.write( "\"x=2\" Reduce\r
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\n" ); document.write( "\n" ); document.write( "So the axis of symmetry is \"x=2\"\r
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\n" ); document.write( "\n" ); document.write( "So the x-coordinate of the vertex is \"x=2\". Lets plug this into the equation to find the y-coordinate of the vertex.\r
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\n" ); document.write( "\n" ); document.write( "\"y=3x%5E2-12x%2B16\" Start with the given polynomial\r
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\n" ); document.write( "\n" ); document.write( "\"y=3%282%29%5E2-12%282%29%2B16\" Plug in \"x=2\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=3%284%29-12%282%29%2B16\" Raise 2 to the second power to get 4\r
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\n" ); document.write( "\n" ); document.write( "\"y=12-12%282%29%2B16\" Multiply 3 by 4 to get 12\r
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\n" ); document.write( "\n" ); document.write( "\"y=12-24%2B16\" Multiply 12 by 2 to get 24\r
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\n" ); document.write( "\n" ); document.write( "\"y=4\" Now combine like terms\r
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\n" ); document.write( "\n" ); document.write( "So the vertex is (2,4)
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