document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=121932>Question 121932</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve  the following systems by addition.  If a unique solution does not exist, state whether the system is inconsistent or dependent.\r<BR>\n" );
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document.write( "X+5Y=10<BR>\n" );
document.write( "-2X-10Y=-20 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #89527 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=89527\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If you try to solve by the elimination method, multiply the first equation by 2 and add to the second equation:\r<BR>\n" );
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document.write( "2(X+5Y=10)<BR>\n" );
document.write( "-2X-10Y=-20\r<BR>\n" );
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document.write( "2X+10Y=20<BR>\n" );
document.write( "-2X-10Y=-20\r<BR>\n" );
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document.write( "The result is 0=0, which means that these equations are actually the SAME LINE.  The equations are therefore said to be \"Dependent.\"\r<BR>\n" );
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document.write( "R^2 \r<BR>\n" );
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